5t^2+-50=0

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Solution for 5t^2+-50=0 equation: 



5t^2+-50=0

We add all the numbers together, and all the variables

5t^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{10}=0$

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